2x^2-14x-48=40

Solution for 2x^2-14x-48=40 equation:

2x^2-14x-48=40

We move all terms to the left:

2x^2-14x-48-(40)=0

We add all the numbers together, and all the variables

2x^2-14x-88=0

a = 2; b = -14; c = -88;
Δ = b2-4ac
Δ = -142-4·2·(-88)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-30}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+30}{2*2}=\frac{44}{4}
=11
$